解決ASP執(zhí)行DB查詢中的特殊字符問題

進(jìn)行數(shù)據(jù)庫的查詢時(shí)，會(huì)經(jīng)常遇到這樣的情況：
    例如想在一個(gè)用戶數(shù)據(jù)庫中查詢他的用戶名和他的密碼，但恰好該用戶使用的名字和密碼中有特殊的字符，例如單引號(hào)，“|”號(hào)，雙引號(hào)或者連字符“&”。
    例如他的名字是1’test，密碼是A|&900，這時(shí)當(dāng)你執(zhí)行以下的查詢語句時(shí)，肯定會(huì)報(bào)錯(cuò)：
    SQL = "SELECT * FROM SecurityLevel WHERE UID=’" & UserID & "’"
    SQL = SQL & " AND PWD=’" & Password & "’"
    因?yàn)槟愕腟QL將會(huì)是這樣：
    SELECT * FROM SecurityLevel WHERE UID=’1’test’　AND PWD=’A|&900’
    在SQL中，"|"為分割字段用的，顯然會(huì)出錯(cuò)了。現(xiàn)在提供下面的幾個(gè)函數(shù)，專門用來處理這些頭疼的東西：
    Function ReplaceStr (TextIn, ByVal SearchStr As String, _
    ByVal Replacement As String, _
    ByVal CompMode As Integer)
    Dim WorkText As String, Pointer As Integer
    If IsNull(TextIn) Then
    ReplaceStr = Null
    Else
    WorkText = TextIn
    Pointer = InStr(1, WorkText, SearchStr, CompMode)
    Do While Pointer > 0
    WorkText = Left(WorkText, Pointer - 1) & Replacement & _
    Mid(WorkText, Pointer + Len(SearchStr))
    Pointer = InStr(Pointer + Len(Replacement), WorkText, _
    SearchStr, CompMode)
    Loop
    ReplaceStr = WorkText
    End If
    End Function
    Function SQLFixup(TextIn)
    SQLFixup = ReplaceStr(TextIn, "’", "’’", 0)
    End Function
    Function JetSQLFixup(TextIn)
    Dim Temp
    Temp = ReplaceStr(TextIn, "’", "’’", 0)
    JetSQLFixup = ReplaceStr(Temp, "|", "’ & chr(124) & ’", 0)
    End Function
    Function FindFirstFixup(TextIn)
    Dim Temp
    Temp = ReplaceStr(TextIn, "’", "’ & chr(39) & ’", 0)
    FindFirstFixup = ReplaceStr(Temp, "|", "’ & chr(124) & ’", 0)
    End Function
    有了上面幾個(gè)函數(shù)后，當(dāng)你在執(zhí)行一個(gè)sql前，請(qǐng)先使用：
    SQL = "SELECT * FROM SecurityLevel WHERE UID=’" & SQLFixup(UserID) & "’"
    SQL = SQL & " AND PWD=’" & SQLFixup(Password) & "’"